Metric Lab #2 Data, Results, Calculations                         bunch tax 1.         The the vast unwashed of the largest quiz tube was 32.08g. (32.08g) x ( chiliadmg) = 32 080mg. 1         1g         We got this cultivation by compressing the tribulation tube turned on the outstrip and recording the mass to the ne arst one percent of a gram. Then, apply System Analysis, we transformed grams to milligrams.                                 length Measure 2.         The length of the largest test tube was 15 cm. (15cm) x (10mm) = 150mm 1 1cm We got out information employ a metric ruler and rounding the results in centimeters. Then, we measured and recorded it in millimeters.                         suit Deter momentuteation 3.         The am bit of the imbue paper was 128.7 g/cm3. substance abuse formula¦pr2 diam of the circle was 12.8 cm. I then severalised up that by 2 to get the radius (r). p (6.4)2= 128.7 cm2. First we measured the diameter and divided it into two. Then by fitting the data in the formula, we were able to come up with the argona of the round filter paper.                         mass Measurement 4.         The rule book of the largest test tube was 59.7 ml. (59.7ml) x ( 1L. ) = .0597 L. 1 1000ml. We got the volume of the gradational cylinder by pickax it up to the top with piddle and pouring all of it into a measuring tube and breeding from the line where the water reaches. We utilise System Analysis to convert milliliters to liters.                         concentration Determination 5.         The slow-wittedness of ethyl group inebriantic beverage is .778 g/cm3. Density =      !    Mass         Volume Mass = 47.84g. (Alcohol + supply) ? 40.58g. (Test Tube Alone) = 6.99 Volume = 9 ml. Of ethyl alcohol. Density = 6.99g = .778g/ml3.         9 ml. First, we had to weigh the tube by itself, which was subtracted by the mass of the tube and the alcohol to image the mass of the alcohol. Then, I divided that by the heart and soul of alcohol to find the niggardliness of ethyl alcohol, which is less softened than water. 6.         The density of rock # 14 was 3.104 g/cm3. Density =         Mass         Volume Mass = 22.94g (rock) Volume = 69 ml. (Water + Rock) ? 60 ml. (Water alone) = 9 ml. Density = 22.94g = 3.104 g/ml 3.         9 ml. I apply the same process to find density as I did in #5. Except, instead of having to find the contrasting in Mass, I had to find the difference in Volume. Questions: 1.         Are a of paper = Length x Width Area= 8.5in. x 11in. = 93.5 in2. 2.         How many minuteonds are in a solar day? 1 Day = (24 hr) x (60 min) x (60 sec) = 86 400 s/day.         1 day         1 hr         1 min                         3.         Convert the interest showing unit analysis: a.         35.5 km = m 35.5 km = 1000 m = 35 000 m                 1 km make: 35 000 m                 b. cxxv mm = cm                 125 mm = 1 cm = 12.5 cm                         10mm                 Answer: 12.5 cm                 c. 8.66 kg = mg                 8.66 kg = 1000 g x 1000mg = 8 660 00! 0 mg                         1 kg         1 g                 Answer: 8 660 000 mg                 d. 2.50 nm = m                 2.50 nm = 1 000 000 000 m = 2 calciferol 000 000 m                                 1 nm                 Answer: 2 viosterol 000 000 m                 e. 45.0 s = h                 45.0 s = 1 min x 1 hr = .013 hr                         60 sec 60 min                 Answer: .013 hr                 f. 9.9 mL = L                 9.9 mL = 1L . = .01 L                                 1000 mL                 Answer: .01 L Question #4 To use Unit Analysis, you engender of divide to the right the closest converting scale to the unit you are stressful to reduce or make larger. You are converting using a method that you can show your work and find where you do your mistake easily. If you want to get a across-the-board essay, commit it on our website: OrderCustomPaper.com
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